36=0.59.8*t^2

Solution for 36=0.59.8*t^2 equation:

36=0.59.8t^2

We move all terms to the left:

36-(0.59.8t^2)=0

We get rid of parentheses

-0.59.8t^2+36=0

We add all the numbers together, and all the variables

-0.472t^2+36=0

a = -0.472; b = 0; c = +36;
Δ = b2-4ac
Δ = 02-4·(-0.472)·36
Δ = 67.968
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{67.968}}{2*-0.472}=\frac{0-\sqrt{67.968}}{-0.944}
=-\frac{\sqrt{}}{-0.944}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{67.968}}{2*-0.472}=\frac{0+\sqrt{67.968}}{-0.944}
=\frac{\sqrt{}}{-0.944}
$